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I am having some difficulty figuring out how to do this integral analytically.
∫r1-x*I0(alpha*r)dr
I have attempted to do integration by parts, but am unable to find any recursion. This would be easy if x was not variable. Also, I have attempted just expanding this term into a Taylor series, but this is not resulting in satisfying results. Any thoughts on how I might approach this one?
tried: u= I0(alpha*r) and dv=r1-x
also tried: dv=r*I0(alpha*r) and u= r-x
∫r1-x*I0(alpha*r)dr
I have attempted to do integration by parts, but am unable to find any recursion. This would be easy if x was not variable. Also, I have attempted just expanding this term into a Taylor series, but this is not resulting in satisfying results. Any thoughts on how I might approach this one?
tried: u= I0(alpha*r) and dv=r1-x
also tried: dv=r*I0(alpha*r) and u= r-x