Negative Light Speed: Explaining the Physical Meaning of -c

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Discussion Overview

The discussion centers on the concept of negative light speed, specifically the implications of using -c in the context of the equation e=mc^2. Participants explore the physical meaning of negative values for the speed of light and the mathematical validity of such interpretations.

Discussion Character

  • Debate/contested

Main Points Raised

  • One participant suggests that if e=mc^2, then (e/m)1/2 could yield either +c or -c, prompting a question about the physical meaning of -c.
  • Another participant argues that e=mc^2 should not be used to derive "c," emphasizing that "c" is a defined constant of 299792458 m/s.
  • A different participant states that while mathematically -c exists, it is considered a non-physical result and is therefore ignored in practical applications of the e=mc^2 equation.
  • One participant reiterates the previous point about not using e=mc^2 to find "c" and provides an analogy with a different equation to clarify their perspective.

Areas of Agreement / Disagreement

Participants express differing views on the validity and implications of negative light speed, with no consensus reached on the physical meaning of -c or its relevance in the context of e=mc^2.

Contextual Notes

There are limitations regarding the assumptions made about the applicability of e=mc^2 and the definitions of constants involved, which remain unresolved in the discussion.

renerob
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If e=mc^2, then (e/m)1/2= either +c or -c. What is the physical meaning of minus c?
 
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e=mc^2 shouldn't be used to try to find "c". "c" is a defined constant of 299792458 m/s.
 
Mathematically -c exists, but this is a non-physical result, and is therefore ignored when using the e=mc2 equation. :)
 
Matterwave said:
e=mc^2 shouldn't be used to try to find "c". "c" is a defined constant of 299792458 m/s.

Precisely. Imagine the equation like this:
[tex]E=m(2)^2[/tex]
[tex]2=\pm \sqrt{\frac{E}{m}}[/tex]

Hope this clarifies.
 

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