Negative Numbers and Logarithms: Is it really wrong?

Hepic
Messages
118
Reaction score
0
I know that in logarithms we can not set as base a negative number,but look at this(in the brackets I will put the base.): log(-2)-8=3 Mathematics say that is wrong,but why?
If we tell -2^3=-8 we have a correct result.
So? Thank you!
 
Mathematics news on Phys.org
That is certainly true.

But:
You'll only be able to find such matches for some INTEGER values.

With any positive number distinct from 1 as chosen as base, we can, with the associated logarithm function represent EVERY positive number as a power of our base.

Having a negative number as your base, however, you cannot gain this type of general usage, that is, a continuous logarithm function covering, say, all the negative numbers is impossible to construct.
---------------------------------------------------------------------
Thus, for simplicity, we say that you can't have a negative number as your base.
 
  • Like
Likes 1 person
That was very clear answer. I hope to be many other guys like you in this forum
 
You are welcome! There are many such guys here. :smile:
 
Last edited:
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. In Dirac’s Principles of Quantum Mechanics published in 1930 he introduced a “convenient notation” he referred to as a “delta function” which he treated as a continuum analog to the discrete Kronecker delta. The Kronecker delta is simply the indexed components of the identity operator in matrix algebra Source: https://www.physicsforums.com/insights/what-exactly-is-diracs-delta-function/ by...
Fermat's Last Theorem has long been one of the most famous mathematical problems, and is now one of the most famous theorems. It simply states that the equation $$ a^n+b^n=c^n $$ has no solutions with positive integers if ##n>2.## It was named after Pierre de Fermat (1607-1665). The problem itself stems from the book Arithmetica by Diophantus of Alexandria. It gained popularity because Fermat noted in his copy "Cubum autem in duos cubos, aut quadratoquadratum in duos quadratoquadratos, et...
I'm interested to know whether the equation $$1 = 2 - \frac{1}{2 - \frac{1}{2 - \cdots}}$$ is true or not. It can be shown easily that if the continued fraction converges, it cannot converge to anything else than 1. It seems that if the continued fraction converges, the convergence is very slow. The apparent slowness of the convergence makes it difficult to estimate the presence of true convergence numerically. At the moment I don't know whether this converges or not.
Back
Top