Net flux through a cylinder from a point charge

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SUMMARY

The discussion centers on the net electric flux through a cylinder when influenced by a point charge located outside one end. According to Gauss' law, a charge outside a closed surface, such as a cylinder, does not contribute to the net electric flux through that surface. The flux through the nearest face of the cylinder is negative due to the electric field direction, while the flux through the further face is positive but smaller in magnitude. The total flux around the surface remains positive, confirming that external charges do not alter the net flux through the closed surface.

PREREQUISITES
  • Understanding of Gauss' Law in electrostatics
  • Familiarity with electric field concepts
  • Knowledge of electric flux calculations
  • Basic principles of closed surfaces in electromagnetism
NEXT STEPS
  • Study Gauss' Law applications in various geometries
  • Learn about electric field calculations from point charges
  • Explore the concept of electric flux in different scenarios
  • Investigate the implications of external charges on closed surfaces
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Students of electromagnetism, physics educators, and anyone interested in understanding electric flux and Gauss' law applications in real-world scenarios.

henry3369
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Homework Statement


My book demonstrates how a uniform electric field through a box generates a net flux of zero. I was wondering if the same would happen from a point charge outside of the cylinder on one end instead of a uniform electric field.

Homework Equations


Flux = E⋅A

The Attempt at a Solution


My book says that charges outside of the surface do not give a net electric flux through the surface. So does that mean if a positive point charge is at one end of the cylinder, all the flux cancels out?

The flux through the nearest face would be negative because E and A are in opposite directions and the flux on the other end would be positive BUT smaller in magnitude because E is smaller (because the distance would increase) while A stays the same. And the flux around the surface would be positive.
So is:
Φnearest face = Φfurther face + Φaround the cylinder ?
 
Physics news on Phys.org
Yes, you have the right idea. A consequence of Gauss' law is that the net flux through any closed surface is proportional to the charge enclosed. A charge outside the closed surface cannot create a net flux through the surface.
 

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