Net magnetic force in unit-vector notation

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The discussion focuses on calculating the net magnetic force on a bent wire in a uniform magnetic field. The wire, carrying a current of 2.0 A and making a 65° angle with the x-axis, has each straight section measuring 2.0 m. The magnetic field is given as 4.0 kT, leading to a calculated force magnitude of 29 N using the formula FB = iLBsin(φ). The direction of the magnetic force is determined using the right-hand rule, which is essential for understanding the orientation of the force relative to the magnetic field. The calculations and concepts are crucial for solving similar physics problems involving magnetic forces.
Mike88
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Homework Statement


The bent wire shown in the figure below lies in a uniform magnetic field. Each straight section is 2.0 m long and makes an angle of θ = 65° with the x axis, and the wire carries a current of 2.0 A.
28-39.gif


(a) What is the net magnetic force on the wire in unit-vector notation if the magnetic field is 4.0k^T?
magnitude [answer] N , direction [ ]

Homework Equations


FB = iLBsin(phi)

The Attempt at a Solution


given i = 2A, L = 2m, B=4kT sin(θ) = 65° i got 2*2*4*sin(65) = 14.5 * 2 for other wire = 29N
 
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Mike88 said:

Homework Equations


FB = iLBsin(phi)
This gives you the magnitude of the force on the wire segment. Note that phi is the angle between iL and B. What direction is the B field?

What's the direction of the magnetic force on the wire segment? (Use the right hand rule.)
 
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