New to physics. with some solutions

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The discussion revolves around a newcomer to physics seeking help with two problems involving kinetic friction and potential energy. For the cyclist problem, it was noted that the data provided is overdetermined and inconsistent, making it unsolvable without assumptions. The second problem regarding the roast's mass was approached using the potential energy formula, leading to a calculated mass of 5.95 kg. Participants emphasized the importance of showing work before receiving equations to aid learning. The conversation highlights the challenges of self-study in physics and the need for clear problem-solving approaches.
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Hello. I am trying to learn physics on my own. I have always thought it was a neat thing.

I am wondering if you could show me how to do these solutions. I can't figure it out.

#1 A cyclist (total mass of 68kg including the bike) traveling initially at 6.5m/s slams on the brakes and skids to a stop in 9.4m. The coefficient of kinetic friction between the tires and the trail is 0.93

a) Calculate the magnitude of the force of kinetic friction
b) Calculate the work done by the force of friction during the skid

#2 A roast in a refrigerators freezer compartment has a potential energy of 35J relative to the floor if the roast is 1.7m above the ground what is the mass of the roast?

Thanks
 
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ford f100 said:
#2 A roast in a refrigerators freezer compartment has a potential energy of 35J relative to the floor if the roast is 1.7m above the ground what is the mass of the roast?

Thanks

You can use this equation.

U = mgh

U=35J
g=10m/s2
h=1.7m
From this you can get m = .....
 
Ok thanks so the answer would be 5.95kg?
 
ford f100 said:
#1 A cyclist (total mass of 68kg including the bike) traveling initially at 6.5m/s slams on the brakes and skids to a stop in 9.4m. The coefficient of kinetic friction between the tires and the trail is 0.93

a) Calculate the magnitude of the force of kinetic friction
b) Calculate the work done by the force of friction during the skid
You can use ##F=ma## and the kinematic equations here.(The equation involving initial speed, final speed, distance and acceleration. Find the acceleration and then find the force acted.)

ford f100 said:
Ok thanks so the answer would be 5.95kg?
Thanks
No. Show the working.
 
Problem #1 is overdetermined - that means it has more data than needed and the given data is not self consistent so it has no solution.
 
dauto said:
Problem #1 is overdetermined - that means it has more data than needed and the given data is not self consistent so it has no solution.

Nice catch. We can still pretend it's on, say planet x, and has a different gravitational acceleration.

Try and find the acceleration first using kinematic equations like

##(V_f)^2 =(V_i)^2 + 2a (Δx)##

##\Delta x =V_i \Delta t + \frac {1}{2} a (\Delta t)^2 ##

##V_i = V_f +a \Delta t ##
 
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dauto said:
Problem #1 is overdetermined - that means it has more data than needed and the given data is not self consistent so it has no solution.

That depends what you assume. The question doesn't say both wheels were locked in the skid. If the bike only has brakes on one wheel, you can calculate the fraction of the bike's weight that is acting on that wheel.
 
Moderator's note -- READ THIS

Please stop providing equations until after the OP has posted an attempt, including work, toward solving the problem.

Learning physics by self-study is to be encouraged and even admired, but please remember our usual guidelines for "homework" help apply to self-study as well.
 
Redbelly98 said:
Moderator's note -- READ THIS

Please stop providing equations until after the OP has posted an attempt, including work, toward solving the problem.

Learning physics by self-study is to be encouraged and even admired, but please remember our usual guidelines for "homework" help apply to self-study as well.


Oh sorry I thought it would be ok considering he seemed to have made an attempt.

Noted for the future
 
  • #10
No worries. :smile: There was an attempt on question #2, but not on #1.
 
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