Hey guys, how would I show that a = g sin(alpha) for the following diagram?
You could start by drawing the forces on the block.
Yeah, I just figured it out.
I determined the Force acting about the hypotenuse, Fm
So, Fm = sin(alpha)*mg
Then, according to Newton's 2nd Law,
Fnet = Fm
ma = sin(alpha)*mg
a = g*sin(alpha)
N.B. The mass is assumed to be on a frictionless surface
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