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Newton's 2nd Law and drawing forces

  1. Oct 16, 2011 #1
    Hey guys, how would I show that a = g sin(alpha) for the following diagram?

    Fig.1.jpg
     
  2. jcsd
  3. Oct 16, 2011 #2
    You could start by drawing the forces on the block.
     
  4. Oct 16, 2011 #3
    Yeah, I just figured it out.

    I determined the Force acting about the hypotenuse, Fm

    So, Fm = sin(alpha)*mg

    Then, according to Newton's 2nd Law,

    Fnet = Fm
    ma = sin(alpha)*mg
    a = g*sin(alpha)

    N.B. The mass is assumed to be on a frictionless surface
     
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