Manni Messages 42 Reaction score 0 Thread starter Oct 16, 2011 #1 Hey guys, how would I show that a = g sin(alpha) for the following diagram?
LawrenceC Messages 1,198 Reaction score 5 Oct 16, 2011 #2 You could start by drawing the forces on the block.
Manni Messages 42 Reaction score 0 Oct 16, 2011 #3 Yeah, I just figured it out. I determined the Force acting about the hypotenuse, Fm So, Fm = sin(alpha)*mg Then, according to Newton's 2nd Law, Fnet = Fm ma = sin(alpha)*mg a = g*sin(alpha) N.B. The mass is assumed to be on a frictionless surface
Yeah, I just figured it out. I determined the Force acting about the hypotenuse, Fm So, Fm = sin(alpha)*mg Then, according to Newton's 2nd Law, Fnet = Fm ma = sin(alpha)*mg a = g*sin(alpha) N.B. The mass is assumed to be on a frictionless surface