Newton's 2nd Law and drawing forces

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Manni
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Hey guys, how would I show that a = g sin(alpha) for the following diagram?

Fig.1.jpg
 
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You could start by drawing the forces on the block.
 
Yeah, I just figured it out.

I determined the Force acting about the hypotenuse, Fm

So, Fm = sin(alpha)*mg

Then, according to Newton's 2nd Law,

Fnet = Fm
ma = sin(alpha)*mg
a = g*sin(alpha)

N.B. The mass is assumed to be on a frictionless surface