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Newton's identities and matrices

  1. May 21, 2014 #1
    About the Newton's identities:
    Newton_s_identities.png

    I'm right if I state that ek = Ik, pk = tr(Ak) and hk = det(Ak) (being Ik the kth-invariant of the matrix A)?
     
  2. jcsd
  3. May 24, 2014 #2
    PS: being ##A = \begin{bmatrix}
    x_1 & 0 & \cdots & 0 \\
    0 & x_2 & \cdots & 0 \\
    \vdots & \vdots & \ddots & \vdots \\
    0 & 0 & \cdots & x_n \\
    \end{bmatrix}##
     
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