Newton's Law- 3 objects on a pulley

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SUMMARY

The discussion focuses on solving a physics problem involving three objects connected by strings over a frictionless pulley. The user initially calculated the acceleration as 9.8 m/s², while the correct answer is 1.63 m/s². The error was identified as a sign mistake in the equations governing the forces acting on the masses. By correctly assigning the direction of acceleration, the user was able to arrive at the correct acceleration value of 1.6 m/s².

PREREQUISITES
  • Understanding Newton's Second Law of Motion
  • Familiarity with tension in strings and pulleys
  • Ability to solve simultaneous equations
  • Knowledge of gravitational force calculations
NEXT STEPS
  • Review Newton's Laws of Motion for clarity on force interactions
  • Practice problems involving multiple masses on pulleys
  • Learn about free-body diagrams to visualize forces
  • Explore advanced topics in dynamics, such as friction and rotational motion
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Students studying physics, particularly those focusing on mechanics, as well as educators looking for examples of problem-solving techniques in dynamics.

johnsonandrew
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Homework Statement



p4-62alt.gif


Three objects are connected by light strings as shown in Figure P4.62. The string connecting the m1 = 5.00 kg mass and the m2 = 4.00 kg mass passes over a light frictionless pulley.

a) find the acceleration of each object and
b) the tension in the two strings




Homework Equations



sumF = m*a

sumF1= m1*a = T1 - m1*g
sumF2= m2*a = T1 - m2*g - T2
sumF3= m3*a = T2 - m3*g



The Attempt at a Solution



I combined equations sumF1 and sumF2:

m1*a = T1 - m1*g
-m2*a = -T1 + m2g +T2

to get rid of one variable, T1, and I got

m2*g - m1*g + T2 = m1a - m2a

then in the sumF3 equation I solved for T2,
T2 = m3*a + m3*g

and plugged that into the above equation to get
m2*g - m1*g + (m3*a + m3*g) =m1*a - m2*a

I then plugged in my knowns to get 9.8 m/s/s, while the answer is supposed to be 1.63 m/s/s.

Can anyone please help? Where did I go wrong? I thought I understood this..
 
Last edited:
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johnsonandrew said:

Homework Statement



p4-62alt.gif


Three objects are connected by light strings as shown in Figure P4.62. The string connecting the m1 = 5.00 kg mass and the m2 = 4.00 kg mass passes over a light frictionless pulley.

a) find the acceleration of each object and
b) the tension in the two strings




Homework Equations



sumF = m*a

sumF1= m1*a = T1 - m1*g
sumF2= m2*a = T1 - m2*g - T2
sumF3= m3*a = T2 - m3*g



The Attempt at a Solution



I combined equations sumF1 and sumF2:

m1*a = T1 - m1*g
-m2*a = -T1 + m2g +T2

to get rid of one variable, T1, and I got

m2*g - m1*g + T2 = m1a - m2a

then in the sumF3 equation I solved for T2,
T2 = m3*a + m3*g

and plugged that into the above equation to get
m2*g - m1*g + (m3*a + m3*g) =m1*a - m2*a

I then plugged in my knowns to get 9.8 m/s/s, while the answer is supposed to be 1.63 m/s/s.

Can anyone please help? Where did I go wrong? I thought I understood this..
you're on track, but the stuff on the left accelerates up, and the stuff on the right acceleartes with the same magnitude, except it accelerates down, You've slipped up on your plus and minus signs.
 
Ohh. I was wondering about that. So on the right side down would be positive if I took up to be positive on the left?
 
johnsonandrew said:
Ohh. I was wondering about that. So on the right side down would be positive if I took up to be positive on the left?
Yes, that should work.
 
Ahhh and it did. It gave me 1.6! Thanks a lot!
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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