Newton's Law- 3 objects on a pulley

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Homework Help Overview

The problem involves three objects connected by strings over a frictionless pulley, focusing on calculating the acceleration of each object and the tension in the strings. The masses involved are m1 = 5.00 kg, m2 = 4.00 kg, and a third mass m3, which is not specified in detail.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the application of Newton's laws to derive equations for the forces acting on each mass. There is an exploration of combining equations to eliminate variables and a focus on the signs associated with acceleration and tension. Questions arise regarding the correct assignment of positive and negative directions in the context of the problem.

Discussion Status

Some participants have provided guidance on the sign conventions used in the equations, suggesting that the direction of acceleration affects the signs in the equations. There is acknowledgment of a participant's realization regarding the sign convention, leading to a corrected calculation that aligns more closely with expected results.

Contextual Notes

The original poster expresses confusion about their calculations and seeks clarification on where they may have gone wrong. The discussion highlights the importance of correctly interpreting the direction of forces and accelerations in the context of the problem.

johnsonandrew
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Homework Statement



p4-62alt.gif


Three objects are connected by light strings as shown in Figure P4.62. The string connecting the m1 = 5.00 kg mass and the m2 = 4.00 kg mass passes over a light frictionless pulley.

a) find the acceleration of each object and
b) the tension in the two strings




Homework Equations



sumF = m*a

sumF1= m1*a = T1 - m1*g
sumF2= m2*a = T1 - m2*g - T2
sumF3= m3*a = T2 - m3*g



The Attempt at a Solution



I combined equations sumF1 and sumF2:

m1*a = T1 - m1*g
-m2*a = -T1 + m2g +T2

to get rid of one variable, T1, and I got

m2*g - m1*g + T2 = m1a - m2a

then in the sumF3 equation I solved for T2,
T2 = m3*a + m3*g

and plugged that into the above equation to get
m2*g - m1*g + (m3*a + m3*g) =m1*a - m2*a

I then plugged in my knowns to get 9.8 m/s/s, while the answer is supposed to be 1.63 m/s/s.

Can anyone please help? Where did I go wrong? I thought I understood this..
 
Last edited:
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johnsonandrew said:

Homework Statement



p4-62alt.gif


Three objects are connected by light strings as shown in Figure P4.62. The string connecting the m1 = 5.00 kg mass and the m2 = 4.00 kg mass passes over a light frictionless pulley.

a) find the acceleration of each object and
b) the tension in the two strings




Homework Equations



sumF = m*a

sumF1= m1*a = T1 - m1*g
sumF2= m2*a = T1 - m2*g - T2
sumF3= m3*a = T2 - m3*g



The Attempt at a Solution



I combined equations sumF1 and sumF2:

m1*a = T1 - m1*g
-m2*a = -T1 + m2g +T2

to get rid of one variable, T1, and I got

m2*g - m1*g + T2 = m1a - m2a

then in the sumF3 equation I solved for T2,
T2 = m3*a + m3*g

and plugged that into the above equation to get
m2*g - m1*g + (m3*a + m3*g) =m1*a - m2*a

I then plugged in my knowns to get 9.8 m/s/s, while the answer is supposed to be 1.63 m/s/s.

Can anyone please help? Where did I go wrong? I thought I understood this..
you're on track, but the stuff on the left accelerates up, and the stuff on the right acceleartes with the same magnitude, except it accelerates down, You've slipped up on your plus and minus signs.
 
Ohh. I was wondering about that. So on the right side down would be positive if I took up to be positive on the left?
 
johnsonandrew said:
Ohh. I was wondering about that. So on the right side down would be positive if I took up to be positive on the left?
Yes, that should work.
 
Ahhh and it did. It gave me 1.6! Thanks a lot!
 

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