(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Three objects are connected by light strings as shown in Figure P4.62. The string connecting the m1 = 5.00 kg mass and the m2 = 4.00 kg mass passes over a light frictionless pulley.

a) find the acceleration of each object and

b) the tension in the two strings

2. Relevant equations

sumF = m*a

sumF1= m1*a = T1 - m1*g

sumF2= m2*a = T1 - m2*g - T2

sumF3= m3*a = T2 - m3*g

3. The attempt at a solution

I combined equations sumF1 and sumF2:

m1*a = T1 - m1*g

-m2*a = -T1 + m2g +T2

to get rid of one variable, T1, and I got

m2*g - m1*g + T2 = m1a - m2a

then in the sumF3 equation I solved for T2,

T2 = m3*a + m3*g

and plugged that into the above equation to get

m2*g - m1*g + (m3*a + m3*g) =m1*a - m2*a

I then plugged in my knowns to get 9.8 m/s/s, while the answer is supposed to be 1.63 m/s/s.

Can anyone please help? Where did I go wrong? I thought I understood this..

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# Homework Help: Newton's Law- 3 objects on a pulley

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