Newton's Laws Finding Applied Force and other Forces

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SUMMARY

The discussion focuses on applying Newton's Laws to determine the acceleration of a skier, Sean, with a mass of 50 kg on a rough patch of snow with a coefficient of friction of 0.20. The gravitational force acting on Sean is calculated as 490.5 N. The frictional force is derived using the equation Ff = μFn, resulting in a frictional force of 98.1 N. The challenge lies in calculating the applied force to find the net force, which is essential for applying Newton's second law (F = ma).

PREREQUISITES
  • Understanding of Newton's Laws of Motion
  • Knowledge of friction coefficients and their application
  • Ability to perform basic force calculations
  • Familiarity with free body diagrams
NEXT STEPS
  • Study the derivation of forces in free body diagrams
  • Learn how to calculate net force using F = ma
  • Explore the relationship between frictional force and normal force
  • Investigate real-world applications of Newton's Laws in skiing dynamics
USEFUL FOR

Students studying physics, educators teaching mechanics, and anyone interested in understanding the application of Newton's Laws in real-world scenarios such as skiing.

jackilynn
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1. Sean the skier is headed for a rough patch of snow with the coeffcient of friction 0.20. Find his acceleration if his mass is 50 kg.
2. F=ma, coeffcient of friction=Ff/Fn
3. Fgravity = 490.5 using the equation coeffcient of friction=Ff/Fn we get 0.20 = Ff/490.5 which equals Ff = 98.1
This is where i get stuck. i do not know how to find the Force applied to use it to find the sum of the two forces (force applied and force of friction) to plug into the equation F= ma.
 
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The sum of forces equals ma (Newtons 2nd law). Use it to write down the equation(s) to be solved.
You know that the vertical acceleation is zero:
[itex]0= N - mg\\<br /> F_{fric} = \mu N=\mu mg\\<br /> \sum F_{horizontal} = ma = -F_{fric}[/itex]
So never plug into any equation unless you have a good reason
 

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