Newton's laws of motion -- Force of gravity on a skydiver

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SUMMARY

The discussion centers on calculating the force of gravity acting on a skydiver using Newton's laws of motion. The formula applied is force of gravity = mass x acceleration, with a mass of 75 kg and an acceleration due to gravity of 9.8 m/s², resulting in a force of 735 N. Participants clarify that the force of gravity remains constant at 735 N after landing, as it only changes with variations in mass.

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kara123
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Homework Statement
A 75 kg skydiver jumps out of an airplane. Calculate the force of gravity acting on him when he jumps and after he has landed. Explain any differences
Relevant Equations
Fnet=ma
I think you would do force of gravity= mass x acceleration

acceleration of gravity= 9.8 m/s
mass 75 kg
75kg x 9.8 m/s
=735 N

i don't know if that's right but i have no idea how to calculate it after he lands, any help would be greatly appreciated!
 
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kara123 said:
i don't know if that's right but i have no idea how to calculate it after he lands
Looks good to me. Question for you: Does the force of gravity change when he lands?
 
kara123 said:
... i have no idea how to calculate it after he lands, any help would be greatly appreciated!
It's a trick question. Knowing that, take a shot at it.
 
Doc Al said:
Looks good to me. Question for you: Does the force of gravity change when he lands?
it does not so it would remain the same after he lands then. The force of gravity would only change in this situation if the mass changes?
 
kara123 said:
it does not so it would remain the same after he lands then. The force of gravity would only change in this situation if the mass changes?
Right! As @russ_watters said, it's kind of a trick question.
 
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