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## Homework Statement

Mass of Block A = 1 kg

Mass of Wedge B = 2 kg

Inclination of Wedge is 37°

and Cos 37° = 4/5

The wedge is given an acceleration of 5 ms

^{-2}

Find -

1. Acceleration of Block wrt Wedge

2. Normal Force

## Homework Equations

Newton's Law for a System (hereby referred as NLS)

∑f

_{ext}= m

_{1}a

_{1}+m

_{2}a

_{2}......+m

_{n}a

_{n}

## The Attempt at a Solution

Let the Acceleration of Block wrt Wedge be λ along the inclination.

In Y axis, there is only one Ext force i.e. The gravity and ∑f

_{net}in Y direction is m

_{1}g+ m

_{2}g = (m

_{1}+ m

_{2})g

Therefore in Y axis using Newton's Law for a System,

m

_{A}a

_{A}+ m

_{B}a

_{B}= (m

_{1}+ m

_{2})g

but in Y axis , a

_{A}= 0

and a

_{b}in Y axis = λsinθ + a

_{A}cos 90

= λsinθ + 0

= λsinθ

Therefore, m

_{B}a

_{B}= (m

_{1}+ m

_{2})g

1 (λsin(θ)) = (1 + 2)g

λ sin 37° = (3)10

λ(3/5) = 30

λ = 50

but using pseudo force, λ = 2 ms

^{-2}which is correct answer in the Answer Key

Where am I going Wrong?

Please Help