Nim Game: Find Proof for D > A, E > B, F > C

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The discussion revolves around the Nim game and the relationship between three piles of objects, denoted as A, B, and C. Participants are exploring whether the conditions D > A, E > B, and F > C can be satisfied, given the definitions of D, E, and F in relation to the Nim-sum X. There is confusion regarding the concept of Nim-sum, with one participant seeking clarification on its definition and implications. It is suggested that if X is greater than zero, then the inequalities D > A, E > B, and F > C hold true. The conversation highlights the need for a clearer understanding of the Nim-sum to address the posed mathematical question.
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Hi all, ok there are 3 piles containing objects; Pile A, Pile B and Pile C.

Let the Nim-sum of all 3 piles be denoted as X.

Let Pile A and Pile B and Pile C contain objects.
( In Nim-Sum )

A + X = D

B + X = E

C + X = F

As we are currently in research of a math project, we are wondering if there is a case whereby D > A, E > B, and F > C. If not, what is the proof?
 
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Perhaps I am not understanding the question. The number of objects in each pile are A, B, C respectively. What do you mean by "Nim-sum"? Certainly if X> 0 then it must be the case that D> A, E> B, and F> C.
 
unscientific said:
Hi all, ok there are 3 piles containing objects; Pile A, Pile B and Pile C.

Let the Nim-sum of all 3 piles be denoted as X.

Let Pile A and Pile B and Pile C contain objects.
( In Nim-Sum )

A + X = D

B + X = E

C + X = F

As we are currently in research of a math project, we are wondering if there is a case whereby D > A, E > B, and F > C. If not, what is the proof?

I don't know what a Nim-Sum is, but from what you have
D>A\Leftrightarrow E>B\Leftrightarrow F>C\Leftrightarrow X>0

so you're just asking if the Nim-Sum is always negative. Well, define it for us and we'll see!
 
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According to wikipedia, a nim-sum is an operation used in game theory.
 
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