Nodal analysis trying to find Voc

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SUMMARY

The discussion focuses on solving for the open-circuit voltage (Voc) in a circuit using nodal analysis. The user successfully calculated the voltage at node VB as 35V, but faced confusion regarding the combination of resistors in the nodal equations. The 60 ohm and 10 ohm resistors were combined due to their isolation from node b, while the 25 ohm and 10 ohm resistors were not combined because they are part of a node with a defined potential. To find Voc, the user is advised to introduce an additional node, VC, and recalculate the equations accordingly.

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jdawg
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Homework Statement


Find Voc

Homework Equations

The Attempt at a Solution


This is what I have:

(VA-9)/5 +VA/5 + 1.8 = 0
VA=0

-1.8 + VB/(60+10) +(VB-9)/20
VB=35

What I'm confused about is why you combine the 60 ohm and 10 ohm resistors for the VB nodal equation, but not the 25 ohm and 10 ohm resistor for the VA nodal equation. Is it because the grounding symbol is directly below the 25 ohm resistor? Thanks!
 

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By adding the 60 and 10 ohm resistors together you've treated them as an isolated branch, ignoring the "tap" that is the terminal "b". This is okay as far as it goes because terminal b is open and no current can flow into or out of it. So it's not really a matter of the ground symbol being directly below VA that prevents you from combining the 25 and 10 ohm resistors, but rather that it is a node that happens to be there. It just happens to be the reference node with a defined potential (0 V).

Note that what you have found is the potential at VB with respect to the reference (ground) node, not the voltage Voc.

To remedy this you could add a node at b, maybe call it VC. Then redo your node equations accordingly and solve for Voc = VB - VC. Alternatively, knowing the potential across the branch you can determine the current in the branch and hence determine the potential drop across the 60 ohm resistor.
 
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Thanks, great explanation!
 

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