MHB Noetherian Rings - Dummit and Foote - Chapter 15 - Exercise 2a

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The discussion focuses on Dummit and Foote's Chapter 15 Exercise 2(a), which requires demonstrating that the ring of continuous real-valued functions on the interval [0, 1] is not Noetherian. Participants suggest two explicit infinite increasing chains of ideals to prove this: one consisting of continuous functions vanishing on the interval [0, 1/n] and another generated by the functions $$f_n(x)=x^{1/n}$$. Both approaches effectively illustrate the non-Noetherian property of the ring.

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  • Understanding of Noetherian rings and their properties
  • Familiarity with continuous functions and their behavior on intervals
  • Knowledge of ideals in ring theory
  • Basic concepts of algebraic structures as presented in Dummit and Foote
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  • Study the properties of Noetherian rings in greater detail
  • Explore examples of infinite increasing chains of ideals in various rings
  • Learn about the implications of non-Noetherian rings in algebraic geometry
  • Investigate the role of continuous functions in functional analysis
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Mathematicians, algebraists, and students studying ring theory, particularly those focusing on Noetherian properties and continuous functions.

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In Dummit and Foote Chapter 15 Exercise 2(a) on page 668 reads as follows:

Show that the following ring is not Noetherian by exhibiting an explicit infinite increasing chain of ideals:

- the ring of continuous real valued functions on [0, 1]I would appreciate help on this exercise.

Peter

[This has also been posted on MHF]
 
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Peter said:
In Dummit and Foote Chapter 15 Exercise 2(a) on page 668 reads as follows:

Show that the following ring is not Noetherian by exhibiting an explicit infinite increasing chain of ideals:

- the ring of continuous real valued functions on [0, 1]I would appreciate help on this exercise.
You could take the n'th ideal to be the set of continuous functions on [0,1] that vanish on the interval [0,1/n].
 
Another solution. Let the nth ideal be the principle ideal generated by the function $$f_n(x)=x^{1/n}$$.
 
johng said:
Another solution. Let the nth ideal be the principal ideal generated by the function $$f_n(x)=x^{1/n}$$.
That is the algebraist's solution, mine was the analyst's solution. (Handshake) (Smile)
 

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