Non-elastic collision answer confirmation

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The problem involves a 13-kg block at rest and a 400-gram glob of putty that collides with it and sticks, resulting in a combined motion. After the collision, the block and putty slide 15 cm on a level floor with a coefficient of friction of 0.4. The final velocity after the impact is calculated to be 1.08 m/s. Using this final velocity, the initial speed of the putty is determined to be 36.18 m/s. The calculations confirm the initial speed based on the principles of momentum and friction.
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Homework Statement



A 13-kg block is at rest on a level floor. A 400-gram glob of putty is thrown at the block such that it travels horizontally, hits the block, and sticks to it. The block and putty slide 15cm along the floor. If the coefficient of sliding friction is 0.4, what is the initial speed of the putty?

Homework Equations


The Attempt at a Solution



Okay. I am just going to list my calculations to save the stress of learning LaTeX.

We know the initial velocity of the block being hit (m_{1}) = 0 m/s
With this known, I can find the final velocity after impact.

I have : v_{f} = \sqrt{2\\mu*g*d} = 1.08 m/s

With now the final velocity after collision, I can calculate the initial velocity of object 2, which is the putty using the equation below.

I have : v_{2i} = \frac{m_{1} + m_{2}}{m_{2}} * v_{f} = 36.18 m/s
 
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