Non-elastic collision without outside influence

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In a head-on elastic collision, a ball A collides with a stationary ball B and rebounds at one-fourth its original speed. The relevant equation for this scenario is v(1) = u(1) * (m(1) - m(2)) / (m(1) + m(2)). The challenge lies in substituting v(1) with 1/4 u(1) and determining the mass of ball B. The discussion emphasizes the importance of considering the direction of velocities in the calculations. Understanding these principles is crucial for solving the problem accurately.
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A ball A of mass makes a head-on elastic collision with a second ball B (at rest) and rebounds in the opposite direction with a speed equal to one-fourth its original speed. What is the mass of the second ball B?

I think an appropriate equation for this is v(1)= u(1)*(m(1)-m(2))/(m(1)+m(2))

I tried solving this by changing v(1) to 1/4 u(1) and then trying to find something that makes that long equation next to u(1) equal 1/4 but I can't seem to find anything
 
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nhmockus said:
A ball A of mass makes a head-on elastic collision with a second ball B (at rest) and rebounds in the opposite direction with a speed equal to one-fourth its original speed. What is the mass of the second ball B?

I think an appropriate equation for this is v(1)= u(1)*(m(1)-m(2))/(m(1)+m(2))

I tried solving this by changing v(1) to 1/4 u(1) and then trying to find something that makes that long equation next to u(1) equal 1/4 but I can't seem to find anything

Hi nhmockus, welcome to Physics Forums.

Remember that velocities have directions.
 
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