Non-Inverting Non-Ideal OpAmp Gain

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SUMMARY

The discussion focuses on calculating the gain of a non-ideal operational amplifier (OpAmp) in a specific circuit configuration. The user attempts to derive the output-to-input voltage ratio (Vout/Vin) using the formula Vout*(R2 / [R1 + R2]) = Vin + Vout/A, acknowledging that the open-loop gain (A) is not infinite. The conversation highlights the importance of understanding the voltage differences at the OpAmp's inputs (V+ and V-) to accurately compute the gain. The user seeks clarification on these voltage values to progress towards the correct solution.

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jnava
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The first part of this problem was to find the gain using an ideal OpAmp.
I am on the second half of this homework problem, where we find Vout/Vin, aka Gain, using a non ideal OpAmp. The attachment is the picture of the circuit.

I know that since the OpAmp is no longer ideal A no longer goes to infinity, which provides a small input on the negative terminal. So, this is what I have right now...but its not getting me to the correct answer...

Vout*(R2 / [R1 + R2]) = Vin + Vout/A


Is this how I would start to find the gain? Once i get Vout/Vin, I could take the lim as A goes to infinity to verify that, the gain equals the ideal OpAmp.
 

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jnava said:
So, this is what I have right now...but its not getting me to the correct answer...

Vout*(R2 / [R1 + R2]) = Vin + Vout/A

An Op-Amp multiples the difference between the voltage into the positive input and the voltage into the the negative input by its open-loop gain A. In other words,

V_{\text{out}}=A(V_{+}-V_{-})


What are V_{\pm} for the circuit in your diagram?
 

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