Engineering Non Inverting Op-Amp Circuit Analysis

AI Thread Summary
The discussion focuses on analyzing a non-inverting op-amp circuit with a 1V peak sinusoidal input. Participants clarify that the voltage at the non-inverting input (VB) equals the voltage at the inverting input (VA) for proper amplifier operation. They emphasize the importance of understanding the roles of the inverting and non-inverting terminals, noting that the circuit uses negative feedback to stabilize gain. Nodal analysis is recommended as an effective method for solving the circuit, leading to the determination of output voltage (Vout) based on the input voltage and resistor values. The conversation highlights the significance of correctly applying op-amp principles for accurate circuit analysis.
cavalieregi
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Homework Statement


For an input potential (Vin ) which is a 1V (peak) sinusoidal source. Calculate V1 and Vout
upload_2014-11-6_14-49-48.png

Homework Equations


- The laws for an op-amp
- NVM

The Attempt at a Solution


Here is my attempt not sure if correct.
upload_2014-11-6_15-2-34.png
 

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VB = VA otherwise the OP-AMP is not operating as an amplifier. Fix this and you should be right.

This is a non-inverting amplifier, the input being applied to the (+) input.
 
NascentOxygen said:
VB = VA otherwise the OP-AMP is not operating as an amplifier. Fix this and you should be right.

This is a non-inverting amplifier, the input being applied to the (+) input.
Cool, just wondering why it is a negative terminal ?
 
cavalieregi said:
Cool, just wondering why it is a negative terminal ?
Why what is a negative terminal?
 
NascentOxygen said:
Why what is a negative terminal?
On diagram it has (-) for non inverting input.
 
cavalieregi said:
On diagram it has (-) for non inverting input.
(-) is the inverting input of the OP-AMP, used here for negative feedback of some output to reduce the gain from its high open-loop value. The circuit's voltage input is applied to the (+) non-inverting input of the OP-AMP.
 
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in addition to Nascent's points, you did some math solving for Vb incorrectly.
you say V1-Vb=0

so that means V1=Vb
why invert Vb?
 
Dont worry so much about what terminal is negative and so forth assuming this is an ideal amp.
To master op amps just stick to nodal analysis.
In this case, V1=A=B. They are all the same voltage.
We know that no current enters the op amp thru the + and - terminals.
Therefore we can easily find the voltage at A or V1 by using a simple voltage divdier. Vin X (10K/57K) = A
Now you know the voltage at B since the + and - terminals are equal in ideal amps.
Now use nodal analysis, (B / 1k) + (B - Vout)/ 10K = 0.
Solve and you are done.
 
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