Normal and Friction Force Relationships went turning curbs

AI Thread Summary
To determine if the frictional force is sufficient for a car to maintain circular motion while turning a curb, one must analyze the relationship between the coefficient of friction, normal force, and the required centripetal force. Given a car mass of 1350 kg, a speed of 15.3 m/s, and a turning radius of 40 m, the calculated acceleration is 0.173 m/s². The required centripetal force to keep the car in circular motion is derived from this acceleration, and the frictional force must equal or exceed this value. With a coefficient of friction of 0.500, the frictional force calculated is 6620 Newtons, which must be compared to the required force to determine if the car can safely navigate the turn. The discussion emphasizes the need to understand the underlying equations rather than just the numerical values.
daniel.j
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how can you tell if the frictional force is great enough to keep a car turning a curb in circular motion based on the coefficient of friction and the normal force?
 
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Acceleration: 0.173 m/s/s
Force is coming from engine but the street is wet with oil.
 
A car with a velocity of 15.3 m/s follows a circular road that has a radius of 40 m. The car has a mass 1350 kg. The pavement is wet and oily so the coefficient o friction between the tires and the road is only .500. The frictionall force that I calculated came out to be 6620 Newtons. Is this frictional force large enough to maintain the car in circular motion?
 
daniel.j said:
A car with a velocity of 15.3 m/s follows a circular road that has a radius of 40 m. The car has a mass 1350 kg. The pavement is wet and oily so the coefficient o friction between the tires and the road is only .500. The frictionall force that I calculated came out to be 6620 Newtons. Is this frictional force large enough to maintain the car in circular motion?
Please don't just tell me numbers. To figure out what you're doing I then I have reverse engineer the calculations. Let's just work with the algebra until we agree the equations.
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