Normal Conditional Distribution

Click For Summary

Discussion Overview

The discussion centers around the properties of normal distributions, specifically regarding the conditional distributions of two random variables, X and Y. Participants explore whether the normality of the conditional distribution of Y given X implies the normality of the conditional distribution of X given Y, considering both independent and dependent cases.

Discussion Character

  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant questions if the normality of the conditional distribution P(Y|X) and the marginal distributions P(X) and P(Y) guarantees that P(X|Y) is also normal.
  • Another participant argues that if P(Y|X) is normal and both P(X) and P(Y) are normal, then P(X|Y) should also be normal, suggesting a proof based on the multiplication of probability density functions (PDFs).
  • A later reply seeks clarification on whether the argument holds if P(X) and P(Y) are not independent, proposing that normality can still be maintained under certain conditions.
  • Another participant notes that in the case of dependent normal distributions, one must consider the covariance matrix and the relationship between the variables, indicating that the product of the PDFs remains normal despite dependencies.

Areas of Agreement / Disagreement

Participants express differing views on whether the normality of the conditional distribution P(X|Y) follows from the normality of P(Y|X) and the marginal distributions. The discussion remains unresolved, with multiple competing perspectives presented.

Contextual Notes

Participants highlight the importance of considering dependencies and covariance when discussing the properties of normal distributions, indicating that the region of integration may affect the calculation of probabilities.

learner928
Messages
21
Reaction score
0
Anyone know answer to below.

If two random variables X and Y are both marginally normal, and conditional distribution of Y given any value of X is also normal.

Does this automatically mean the conditional distribution of X given any value of Y also has to be normal? or not necessarily.
 
Physics news on Phys.org
Hey learner928 and welcome to the forums.

GIven P(Y|X) is Normal, P(X) is Normal, P(Y) is normal so P(X|Y) is proportional to P(Y|X)*P(X) (using a posterior) and if P(Y|X) has normal PDF with P(X) having a normal PDF, then the posterior will also have a normal PDF.

You can prove this by starting off with two PDF expressions P(A) = Normal_PDF_1, P(B) = Normal_PDF_2 and then multiply the two together and show that the product is also a Normal PDF and you're done.
 
chiro said:
Hey learner928 and welcome to the forums.

GIven P(Y|X) is Normal, P(X) is Normal, P(Y) is normal so P(X|Y) is proportional to P(Y|X)*P(X) (using a posterior) and if P(Y|X) has normal PDF with P(X) having a normal PDF, then the posterior will also have a normal PDF.

You can prove this by starting off with two PDF expressions P(A) = Normal_PDF_1, P(B) = Normal_PDF_2 and then multiply the two together and show that the product is also a Normal PDF and you're done.


Thanks Chiro, just to confirm, so your argument still applies even if P(X) and P(Y) are not independent right,

so in conclusion,
Even if P(X) and P(Y) are not independent, if P(X), P(Y) and P(Y|X) are all normal, then P(X|Y) also has to be normal.
 
If they are not independent normal then you will have a covariance matrix with off-diagonal positions, or you will have in general, a relationship where A = f(B) [A and f(A) both normal] so what you should do in this case is use limits that reflect the dependencies (which is what happens in dependent distributions).

You should however be able to prove that the product is normal (even if they are dependent or related) by assuming both have normal PDF and thus the product has a normal PDF.

The big difference will be the region of integration, and how these limits allow you to calculate an actual probability for your final variable.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 30 ·
2
Replies
30
Views
5K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K