If we are simply standing on the ground will our normal force be always equal to our weight besides when we are jumping or when we land on the ground from a fall?
When we are in an elevator, will the normal downwards force on the floor be of our weight (cancelling out our the extra force acted to allow us the gain an acceleration?
Eg I am 10kg and I move up with acceleration of 5m/s^2. Net force=upwards-normal downwards force=upwards-100N=50N. So upwards force is 150N and hence normal downwards force is 150N as well? In other words, the normal downwards force is always equal to weight?
The Attempt at a Solution
I think so, because if we look at the free body diagram (FBD) of me. I have 100N of force acting downwards (weight) but since I have a net force of 50N, so I need 150N of upwards force to counter the 100N of force. So in essence, the normal downwards force can be evaluated by the object's (in this case myself) motion? So for another example, when jumping I experience 10N net force, so my normal downwards force will be my weight plus the additional 10N of force. Totalling to 110N? Thanks for the help!