Normal Force on Vertical Plane

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Homework Help Overview

The problem involves a 70kg climber supported in a vertical "chimney" by friction forces from his back and shoes, with given coefficients of static friction. The objective is to determine the minimum normal force required to prevent slipping, considering the walls are vertical and friction is at the point of impending slipping.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss calculating frictional forces using the formula Ff=mu*n, with some questioning the validity of calculating friction without knowing the normal force. There are attempts to relate the vertical force needed to the climber's weight and the normal force applied against the walls.

Discussion Status

Participants are actively engaging with the problem, with some offering guidance on breaking down the steps. There is a mix of interpretations regarding the relationship between normal force and friction, and the discussion is ongoing without a clear consensus on the approach.

Contextual Notes

Some participants express confusion about the application of concepts from inclined planes to this vertical scenario, indicating a need for clarification on the mechanics involved. The problem also involves varying coefficients of friction in a modified example presented by one participant.

bueckerjl
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Homework Statement


A 70kg climber is suppored in a "chimney" by the friction forces exerted on his back and shoes. The coeffcients of static friction of his feet against the wall and his back against the wall are 0.8 and 0.6 respectively. What is the minimum normal force he needs to apply to keep from slipping? Assume the walls are perfectly vertical and the the frictional forces are at impending slipping.


Homework Equations


F=ma
Ff(frictional force)=mu*n(normal force)
W=mg


The Attempt at a Solution



What I did was calculated the frictional force for the feet and the back using Ff=mu*n
What I came up with was aprox 980Newtons. Then I figured that since static friction is only used as needed, I calculated the climber's weight and I came up with 686N.
That doesn't sound right to me. What am I messing up? Thanks
 
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Welcome to PF,

How did you calculate the minimum frictional force without using the climber's weight?
 
bueckerjl said:
What I did was calculated the frictional force for the feet and the back using Ff=mu*n
What I came up with was aprox 980Newtons.
How can you calculate the friction force without knowing the normal force? (And the normal force is what you need to solve for.)
Then I figured that since static friction is only used as needed, I calculated the climber's weight and I came up with 686N.
Since the friction is just barely enough to prevent slipping, what must the friction force equal?
 
Welcome to PF!

bueckerjl said:
What is the minimum normal force he needs to apply to keep from slipping?

Hi bueckerjl! Welcome to PF! :smile:

Do problems like this one step at a time …

First step: What is the vertical force he needs to apply to keep from falling?

Second step: How will this vertical force be produced?

Your thoughts … ? :smile:
 
NO! Keep going! I need help on this problem. I'm stumped.
Ok so let's start over, For my example everything is the same but the guy is 78 kg
mu of the feet is 0.84 and mu for the back is 0.64.

I found mg = 764
So I need to make the vertical force resisting equal 764.
The vertical force is produce by pressing a normal force against each wall.
I don't know how to get there. I tried treating it as an inclined plane...but cos90 = 0 which means that friction is zero if friction = mu*N.
 
tbaskerv said:
I tried treating it as an inclined plane...but cos90 = 0 which means that friction is zero if friction = mu*N.

Why is that? This has nothing to do with planes.

You're basically there! Use the equation and you're done!
 

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