At what temperature will aluminum have a resistivity that is three times the resistivity of tungsten at room temperature?
Rt=5.6 X 10^-8 ohm*m (The resistivity coefficient of tungsten at 20 degrees celcius)
R0=1.59 x 10^-8 ohm*m (The resistivity coefficient of silver at 20 degrees celcius)
α =3.9 X 10^-3 degrees celsius ^- 1 (Temperature coefficient of resistivity for aluminum)
I am not sure what the initial temperature is, I assume its 20 degrees celcius.
Rt = R0 * ( 1 + α * ΔT)
The Attempt at a Solution
3Rt = R0 * ( 1 + α * ΔT)
I get 11.42 degrees celsius which is wrong?