Temperature to raise resistance

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SUMMARY

The discussion focuses on calculating the temperature required to increase the resistance of a platinum wire by 3%. The initial temperature is given as 15 degrees Celsius, and the temperature coefficient 'a' for platinum is specified as 3.9 x 10^-3. The resistance formula used is R = Ro * [1 + 'a' * (T - To)], where Ro is the initial resistance and To is the initial temperature. The conclusion emphasizes that without an initial resistance value, the calculation can be simplified to R = 1.03 * Ro, leading to the equation Ro = R / 1.03 for further analysis.

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  • Understanding of electrical resistance and its temperature dependence
  • Familiarity with the temperature coefficient of resistance
  • Basic algebra for solving equations
  • Knowledge of platinum's properties as a conductor
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Homework Statement


A platinum wire is originally at 15 degree celsius. Find the required temperature to increase its resistance by 3%.


Homework Equations


R = Ro * [1 + 'a' * (T-To)]
Ro is initial resistance. To is initial temperature.
'Temperature Coefficient' 'a' of platinum at room temperature 20 degree celsius is 3.9 * 10^-3


The Attempt at a Solution


I don't have an initial resistance to start off with. But I do have the initial temperature and the room temperature, To = 15 and T = 20 degree celsius.

Solving for Temperature T = ('a'To + R/Ro) / 'a'
But I don't have any reference resistance to begin with, how do I solve this?
 
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R = R_o[\alpha (T - T_o) + 1]
R = 1.03R_o
 
xcvxcvvc said:
R = 1.03R_o

Can you show how you got this by eliminating all the other variables? Even from this simplified form, there isn't an initial resistance to begin with. Unless...

R_o = R / 1.03

?
 

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