Notation (v*gradient operator)v in Navier-Stokes

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    Navier-stokes Notation
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Discussion Overview

The discussion revolves around the notation and meaning of the expression \((\textbf{v} \cdot \nabla) \textbf{v}\) in the context of the Navier-Stokes equations. Participants explore the gradient operator and its application in fluid dynamics, particularly focusing on how this notation can be expanded and interpreted.

Discussion Character

  • Technical explanation
  • Conceptual clarification
  • Mathematical reasoning

Main Points Raised

  • One participant seeks clarification on the meaning of \((\textbf{v} \cdot \nabla) \textbf{v}\) and requests an expansion of this notation.
  • Another participant explains that \(\nabla\) is the "del" or "nabla" operator and provides a detailed expansion of \(\textbf{v} \cdot \nabla\) in terms of its components, leading to a specific form of \((\textbf{v} \cdot \nabla) \textbf{v}\).
  • A third participant expresses confusion about the notation \( (y + \frac{d}{dx})y \) and inquires whether it is meaningful or can be expanded.
  • A later reply suggests that \( (y + \frac{d}{dx})y \) can be expanded to \( y + \frac{dy}{dx} \).

Areas of Agreement / Disagreement

Participants do not reach a consensus on the broader implications of the notation discussed, particularly regarding the second expression. There is a mix of understanding and confusion among participants regarding the mathematical expansions presented.

Contextual Notes

The discussion includes assumptions about the participants' familiarity with vector calculus and differential operators, which may not be uniformly shared. The notation and its implications are not fully resolved, leaving room for further exploration.

TylerH
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Notation "(v*gradient operator)v" in Navier-Stokes

What does \left( \textbf{v} \cdot \nabla \right) \textbf{v} mean, assuming knowledge of the gradient operator? And, specifically, how would that be expanded? In general, I'm ignorant of the notation \left( f \left( y, \frac{d}{dx}, \frac{d^2}{dx^2}, \ldots \right) y \right) where, for example, f \left( y, \frac{d}{dx}, \frac{d^2}{dx^2}, \ldots \right) could be y + \frac{d}{dx}.

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That is, by the way, the "del" or "nabla" operator. It is specifically only \nabla f(x,y,z, with f a scalar valued function, that is the "gradient". \nabla\cdot \vec{v} is the "gradient" or grad \vec{v} and \nabla\times\vec{v} is the curl \vec{v}.

In any case
\vec{v}\cdot\nabla= v_x\frac{\partial }{\partial x}+ v_y\frac{\partial }{\partial y}+ v_z\frac{\partial }{\partial z}
so that
\vec{v}\cdot\nabla \vec{v}= \left(v_x\frac{\partial }{\partial x}+ v_y\frac{\partial }{\partial y}+ v_z\frac{\partial }{\partial z}\right)v_x\vec{i}+ \left(v_x\frac{\partial }{\partial x}+ v_y\frac{\partial }{\partial y}+ v_z\frac{\partial }{\partial z}\right)v_y\vec{j}+ \left(v_x\frac{\partial }{\partial x}+ v_y\frac{\partial }{\partial y}+ v_z\frac{\partial }{\partial z}\right)v_z\vec{k}
= \left(v_x\frac{\partial v_x}{\partial x}+ v_y\frac{\partial v_x}{\partial y}+ v_z\frac{\partial v_x}{\partial z}\right)\vec{i}+ \left(v_x\frac{\partial v_y}{\partial x}+ v_y\frac{\partial v_y}{\partial y}+ v_z\frac{\partial v_y}{\partial z}\right)\vec{j}+ \left(v_x\frac{\partial v_z}{\partial x}+ v_y\frac{\partial v_z}{\partial y}+ v_z\frac{\partial v_z}{\partial z}\right)\vec{k}
 


Oh, I didn't understand it as well as I thought I did. Thanks.

Just wondering, is \left( y + \frac{d}{dx} \right)y meaningless, or can it be expanded? If it can, what is it?

Thanks for your time.
 


it can be expanded as:
<br /> y+\frac{dy}{dx}<br />
 

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