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## Homework Statement

For a nucleus of A=220, estimate very roughly how many nucleaons would be at the surface.

## Homework Equations

R

_{0}=1.5 x 10

^{-15}

r=A

^{1/3}x R

_{0}

## The Attempt at a Solution

Using the formulas, I calculated R to be 7.2441729 x 10

^{-15}

The book says that the number of nucleons at the surface and the total number of nucleons has a ratio of ~1/r

1/r= 1.3804 x 10

^{14}

I tried the following:

1.3804 x 10

^{14}= 220/x

which didn't make sense...

what am I doing wrong?

Thanks!