In the near future nuclear fusion reactions such as the one shown below may be used to produce electrical power.
2 H ----> He + energy
Physicists have suggested that 50 MW of energy will be sufficient to satisfy the energy needs of these industrial areas. If the nuclear reaction above is only 30% efficient, what mass of deuterium fuel will be needed per day.
atomic mass (21)H = 2.024202 amu and of (42)H = 4.002603
The Attempt at a Solution
I'm in a state of panic right now. I have an exam tomorrow morning and don't get nuclear physics, it really just confuses me :(
Any help at all is appreciated. Please. Please. Please. I'm not one for begging but... please. (Please).
My feeble attempt:
Find mass defect: H - H = 1.988501
= 2.1198 * 10^-27
E = mc^2
= 2.1198*10^-27 * (3*10^8)^2
= 1.9078 * 10^-10 j
Joules needed per day = 50*10^6 * 24 *60*60
= 4.32 *10^11
reactions per day =
4.32*10^11 / 1.9027*10^-10
2.26 * 10^21
total mass needed = 2.014 * 2.26*10^21
4.56 * 10^21 amu
I know im probably wrong. I have no idea what im doing. Its all guessing and confusion. I don't even have the answer to this problem, and its a revision sheet. Ugh. Im going to fail this exam so hard.
If you help me i will be eternally grateful. :)