MHB Number of Positive Integer Pairs for Perfect Squares

AI Thread Summary
The discussion revolves around finding ordered pairs of positive integers \(x\) and \(y\) such that both \(x^2 + 3y\) and \(y^2 + 3x\) are perfect squares. Initial attempts to solve the equations led to no valid pairs, but further exploration suggested that pairs like \((1,1)\), \((2,4)\), and others yield perfect squares. The conversation highlights the need to express \(x\) and \(y\) in terms of other variables to identify valid integer solutions. Ultimately, the thread concludes that there are indeed infinite pairs that satisfy the conditions.
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the number of ordered pairs of positive integers $x,$y such that $x^2 +3y$ and $y^2 +3x$

are both perfect squares

my solution::

http://latex.codecogs.com/gif.latex?\hspace{-16}$Let%20$\bf{x^2+3y=k^2}$%20and%20$\bf{y^2+3x=l^2}$\\%20Where%20$\bf{x,y,k,l\in%20\mathbb{Z^{+}}}$\\%20$\bf{(x^2-y^2)-3(x-y)=k^2-l^2}$\\%20$\bf{(x-y).(x+y-3)=(k+l).(k-l)}$\\%20$\bullet\;\;%20\bf{(x-y)=k+l\;\;,(x+y-3)=k-l}$\\%20$\bullet\;\;%20\bf{(x-y)=k-l\;\;,(x+y-3)=k+l}$\\%20So%20$\bf{x=\frac{2k+3}{2}\notin%20\mathbb{Z^{+}}}$\\%20and%20$\bf{y=\frac{-2l+3}{2}\notin%20\mathbb{Z^{+}}}$\\

no possibilities.

but there is also more possibilities

like $(x-y).(x+y-3) = 1 \times (k^2-l^2) = (k^2-l^2) \times 1$

My Question is that is any pairs for which $x^2+3y$ and $3x^2+y$ are perfect square

Thanks
 
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We have $x^2+3y=(x+a)^2$ for some positive integer $a$ and similar for $y$ and some $b$. Express $x$ and $y$ through $a$ and $b$ and see when $x$ and $y$ are positive integers.
 
what about $(1,1)$?
 
jacks said:
the number of ordered pairs of positive integers $x,$y such that $x^2 +3y$ and $y^2 +3x$

. . . .

My Question is that is any pairs for which $x^2+3y$ and $3x^2+y$ are perfect square

Thanks
I think you just changed the question.
 
jacks said:
My Question is that is any pairs for which $x^2+3y$ and $3x^2+y$ are perfect square
Of course; infinite:
1,1
2,4
3,9
4,16
5,25
...and on...
 
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