Number Theory - How to Prove n^7 is Congruent to n Mod 63

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number theorm -- Euler theorem

Homework Statement



let be an integer that not divisible by 3. Prove that n^7\equivn mod 63

Homework Equations



none

The Attempt at a Solution


it is suffice to prove that n^7\equivn mod 7,n^7\equivn mod 9, i get
n^7\equivn mod 7 by Euler theorem , how to prove n^7\equivn mod 9
 
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Remember that Euler's totient function, \varphi (n) is equal to the number of positive integers less than or equal to n that are coprime to n. What is \varphi (9) and what does that imply by Euler's Theorem?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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