Number theory proof trouble: pesty ellipsis

aohawthorn
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Homework Statement



Prove that

x^n - y^n = (x - y) (x^(n - 1) + (x^(n - 2)y + . . . + xy^(n - 2) + y^(n - 1)

Homework Equations



This is problem 3, section 1-1 from Andrew's "Number Theory," which I'm using for self-study. It follows the section on the "Principle of Mathematical Induction", i.e. "A statement about integers is true for all integers greater than or equal to 1 if (1) it is true for the integer 1, and (ii) whenever it is true for all the integers 1,2, ..., k, then it is true for the integer k + 1." The first two proofs both involve plugging k into an expression, adding (k + 1), and setting the sum equal to the same expression with (k + 1) plugged into it.

The Attempt at a Solution



I don't need a solution - I need to understand the question! I can't figure out what the ellipsis here is representing. In other expressions in the book (e.g. 1^3 + 2^3 + 3^3 + . . . + n^3) the ellipsis obviously represents a sequence of terms leading up to one greatest value n, but I just can't see what sort of "sequence" is represented in this problem! Any help would be deeply appreciated. Again - I'm not looking for the answer, just to understand the question. Thanks a lot!
 
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x^n - y^n = (x - y)\left(\sum_{k=1}^n\ x^{n-k}y^{k-1}\right)

is a version of the formula without ellipses.
 
Aha! Thanks so much - I see it now.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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