Objects Speed og a cylinder and hoop

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SUMMARY

The discussion focuses on calculating the speeds of a cylinder and a hoop at the bottom of a ramp, utilizing the principles of conservation of energy. The moment of inertia for the cylinder is given as I = 1/2 MR², while for the hoop, it is I = MR². The conclusion drawn is that the cylinder will achieve a greater speed than the hoop due to its lower moment of inertia, which allows it to convert more potential energy into kinetic energy as it descends the ramp.

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Homework Statement



Consider both a cylinder of radius Rc and mass mc and a hoop of radius Rh and mass mh. If both are at top of a ramp of length L and at angle theta, what are the objects speeds at the bottom of the ramp

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The Attempt at a Solution

Well, I think that the cylinder will have the greatest speed at the bottom since I= 1/2MR^2 and the hoop is I=MR^2. I don't really get where to go though since we haven't tackled anything like this, just the above answer I put.
 
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You have to give the speeds in terms of the given data. Use conservation of energy.

ehild
 

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