OChem 2 - LiAlH4 vs NaBH4 - Lab Question

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Hey guys! New to the forum here, I've come here several times before for insight on various topics and you guys have always been so helpful!

I noticed I couldn't find anything similar to this question while I was doing my lab report and I'm quite lost, to be honest..

1) Lithium aluminum hydride would also reduce cyclohexanone to cyclohexanol. List three changes that would have to be made to the procedure/conditions to accommodate lithium aluminum hydride, instead of sodium borohydride.

I know that LiAlH4 is more flammable and pyrophoric, I know it is a much stronger reducing agent, but what would you have to change in the procedure/conditions if we were to use it instead of NaBH4? Safety conditions would have to be slightly amended, but I'm not really sure where else to go.

The lab in question was reducing a ketone ( cyclohexanone ) to an alcohol ( cyclohexanol ) using NaBH4 as your reducing agent. It was a pretty simple lab.

Thanks in advance for the help!
 
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DrDu said:
So which solvent did you use with NaBH4?
First step was NaBH4/methanol and quenching step was NaOH/H2O
 
Will it reduce the methanol?

edit: it should help to know that we haven't covered this material in class yet, unfortunately I got the bad lab schedule. This is due in 1hour and I still can't find the answer. I've been watching videos and reading but I'm still so lost :(.
 
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I think I figured it out, I could use LiAlH4 with THF or an ether and then quench with H2O.
 
Thanks for your help! You steered me in the right direction and got me to find the answer.

The first step you would use LiAlH4 in THF or an ether, and then you would hydrolyze that in a second step using an aq. acid, (H3O+/H2O)