Odd Number Possibilities with a Die: 50% (2 Rolls)

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The probability of rolling at least one odd number with a die in two rolls is 75%, calculated by subtracting the chance of rolling two even numbers (25%) from 100%. When rolling three times, the probability of getting at least one odd number increases to approximately 87.5%, derived from the calculation of the chance of rolling all even numbers (1/8 or 12.5%). The discussion emphasizes understanding probability through both combination enumeration and complementary probability. Misunderstandings about calculating these probabilities were clarified during the conversation. The topic highlights the importance of grasping basic probability concepts when dealing with multiple rolls of a die.
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To bring odd number with a die,is 50%.
If I play with the die two times,how possibilities I have to bring odd number?
 
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There would be a 25% chance of getting two odd numbers, 25% chance of two even numbers and a 50% chance of getting one of each. So the probability of getting at least one odd number would be 75%.
 
Yea,I am talking about bringing at least one time "odds".
How we find the 75%?
 
Well you can write out all 36 combinations and add them up. Or you can think of it as 100% less the probabability of getting both even which is 100% - 50%x50% = 100%-25%=75%
 
So If I undestood good,If I play "3" times,for the same result,I have 83,3333%.

Right?
 
No, apparently you didn't understand at all. The probability of getting all three even is (1/2)^3= 1/8= 0.125 so the probability of "at least one head in three rolls" is 1- 0.125= 0.875.
 
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