# Okay i know i totally sux at math

• roxas
In summary, the conversation is about someone asking for help with factorisation questions and someone else providing a summary of the steps to factorise the given expressions. The first expression, 18t^2-2, can be factored into 2(3t+1)(3t-1), while the second expression, 3tx-2sx+15ty-10sy, can be written as (3t-2s)(x+5y).

#### roxas

so can anyone help me with these factorisation questions?

factorise

18t^2 -2

3tx-2sx+15ty-10sy

can anyone please show me the steps thx

Take the first.
Factorize each term on its own. What are the common factors?

Is it really THAT difficult for you to do a single, trivial, independent action on your own??

That is the main reason why you suck at maths:
Not that maths is "difficult", not that you are "dumb", but quite simply your reluctance to DO any maths at all in the first place

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roxas said:
18t^2 -2
Firstly note that there are 2 terms. 18t^2 and -2. These are both divisible by 2, so take a 2 to the front of the brackets and write it like:
2(9t^2 -1)

This will not factorise any further.

roxas said:
3tx-2sx+15ty-10sy
You can write this as x(3t-2s)+5y(3t-2s) by simply taking the x and y terms out of each individual term. Now note that each set of brackets is the same so it can be furthermore factorised to: (3t-2s)(x+5y)

PotatoSalad said:
Firstly note that there are 2 terms. 18t^2 and -2. These are both divisible by 2, so take a 2 to the front of the brackets and write it like:
2(9t^2 -1)

This will not factorise any further.
Do you want to bet on that?
Don't do the homework for OP, by the way, he must show some of his own work first.

roxas said:
so can anyone help me with these factorisation questions?

factorise

18t^2 -2

3tx-2sx+15ty-10sy

can anyone please show me the steps thx

let me do the first one for you...

18t2-2 = 2(9t2-1) = 2(3t+1)(3t-1).

see if you can do the other one.

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