Okay i know i totally sux at math

  • Thread starter roxas
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In summary, the conversation is about someone asking for help with factorisation questions and someone else providing a summary of the steps to factorise the given expressions. The first expression, 18t^2-2, can be factored into 2(3t+1)(3t-1), while the second expression, 3tx-2sx+15ty-10sy, can be written as (3t-2s)(x+5y).
  • #1
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so can anyone help me with these factorisation questions?

factorise

18t^2 -2

3tx-2sx+15ty-10sy

can anyone please show me the steps thx
 
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  • #2
Take the first.
Factorize each term on its own. What are the common factors?
 
  • #3
Is it really THAT difficult for you to do a single, trivial, independent action on your own??

That is the main reason why you suck at maths:
Not that maths is "difficult", not that you are "dumb", but quite simply your reluctance to DO any maths at all in the first place
 
Last edited:
  • #4
roxas said:
18t^2 -2
Firstly note that there are 2 terms. 18t^2 and -2. These are both divisible by 2, so take a 2 to the front of the brackets and write it like:
2(9t^2 -1)

This will not factorise any further.

roxas said:
3tx-2sx+15ty-10sy
You can write this as x(3t-2s)+5y(3t-2s) by simply taking the x and y terms out of each individual term. Now note that each set of brackets is the same so it can be furthermore factorised to: (3t-2s)(x+5y)
 
  • #5
PotatoSalad said:
Firstly note that there are 2 terms. 18t^2 and -2. These are both divisible by 2, so take a 2 to the front of the brackets and write it like:
2(9t^2 -1)

This will not factorise any further.
Do you want to bet on that? :wink:
Don't do the homework for OP, by the way, he must show some of his own work first.
 
  • #6
roxas said:
so can anyone help me with these factorisation questions?

factorise

18t^2 -2

3tx-2sx+15ty-10sy

can anyone please show me the steps thx

let me do the first one for you...

18t2-2 = 2(9t2-1) = 2(3t+1)(3t-1).

see if you can do the other one.
 

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