- #1
transgalactic
- 1,395
- 0
[tex]
f(x)=\frac{1}{1+ln|x|}
[/tex]
the ln|x| part could be -1 when x=e^-1
correct??
f(x)=\frac{1}{1+ln|x|}
[/tex]
the ln|x| part could be -1 when x=e^-1
correct??