Open-Closed Tube: Tension in 24.0cm Wire at Fundamental Frequency

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To find the tension in the wire, both the length of the wire and the length of the open-closed tube must be considered, as they are related through their frequencies. The wire vibrates at its fundamental frequency, while the tube resonates at its second vibrational mode. The key is to equate the frequencies of both systems, using the wave speed of 340 m/s. The discussion emphasizes the need to derive equations for both the vibrating wire and the tube to solve for tension. Understanding the relationship between the two systems is crucial for calculating the correct tension in the wire.
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Here is my question:

A 24.0 cm -long wire with a linear density of 20.0 g/m passes across the open end of an 89.0 cm-long open-closed tube of air. If the wire, which is fixed at both ends, vibrates at its fundamental frequency, the sound wave it generates excites the second vibrational mode of the tube of air. What is the tension in the wire? Assume v=340 m/s

I am confused about the two values for the length. Do I have to use two equations and set them equal to each other? Would all else be the same for both? Please help :frown:
 
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yes you do need to use both lengths, what the systems have in common is frequency where the pipe is in its second vibrational mode, while the string is at its fundamental. Do you know what second mode means here?

so write down some eqns, for both systems and we can go from there.
 
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