Is the Energy Level a Root of the Function in Quantum Operator Theory?

  • Thread starter Thread starter tpm
  • Start date Start date
  • Tags Tags
    Operator Theory
tpm
Messages
67
Reaction score
0
let be:

f( \hat H ) | \Psi > =0 where | \Psi > is an 'Eigenvalue'

of the operator 'T' my question is if in this case the number

\hat T | \Psi > =E_{n} | \Psi > satisfy f( E_{n}) =0

so the energies are precisely the roots of f(x).
 
Physics news on Phys.org
|x> usually means an element in a Hilbert space, doesn't it, Jose? Why is that an 'Eigenvalue'. What is f. What is H? What is H-hat? What is T hat?
 
I believe H is the Hamiltonian and T is the Kinetic Energy operators.

You may have better luck posting this in the Quantum Physics section.
 
Back
Top