Optical Spectrum Analyzers - Confused on Units

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SUMMARY

The discussion clarifies the confusion surrounding the units used in Optical Spectrum Analyzers (OSAs), specifically the resolution measurements expressed in both nanometers (nm) and megahertz (MHz). Users often encounter values such as 0.04 pm / 5 MHz, which represent the differences in measurements rather than direct frequencies or wavelengths. The relationship between frequency and wavelength is established through the speed of light, allowing for conversions between the two. Understanding these units is crucial for selecting an appropriate OSA for specific wavelength spectra analysis.

PREREQUISITES
  • Understanding of optical spectrum analyzers (OSAs)
  • Basic knowledge of wavelength and frequency relationships
  • Familiarity with measurement errors in optical systems
  • Concept of speed of light in relation to frequency and wavelength
NEXT STEPS
  • Research the specifications and capabilities of different Optical Spectrum Analyzers (OSAs)
  • Learn about the mathematical relationship between frequency and wavelength using the speed of light
  • Explore measurement error analysis in optical measurements
  • Investigate advanced resolution techniques in optical spectroscopy
USEFUL FOR

This discussion is beneficial for optical engineers, technicians working with optical spectrum analyzers, and anyone involved in wavelength and frequency measurement in optical systems.

cambridgejohn
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Hi!

I am new to these, and off the bat am confused by the units.

Manufacturers quote resolution either in units of length, e.g. 0.04 nm, or HZ. For example,

0.04 pm / 5MHz
0.16 pm / 20 MHz
0.8 pm / 100 MHz.

I am thrown by this since I thought frequency was the inverse of wavelength. I get the length part and can understand when I look at a plot of Power vs. Wavelength.

I know I am overlooking something obvious...please help!

Thanks!
John
 
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The numbers are not frequencies and wavelengths. The are differences between (or errors in the measurement of) in frequencies and wavelengths.

If a frequency f has wavelength \lambda, then
a frequency of f + 5 Mhz has a wavelength of approximately \lambda - 0.04pm, and so on
 
Thanks. The error concept part helps. I can understand when a wavelength is being measured a higher resolution helps out, and that one needs to only buy an OSA which will discern a certain wavelength spectra. And I can understand how the difference part makes sense for the wavelength.

What are the units of the proportion between the frequencies and wavelengths measured?
 
ok. it all makes sense now. just needed to run through some numeric examples using the speed of light to get numbers. thanks again for your help.
 

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