Optics-Diffraction of Thin Hair

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Homework Help Overview

The problem involves the diffraction of light as it passes around a thin object, specifically a human hair, illuminated by a laser. The setup includes measurements related to the diffraction pattern produced on a screen, with parameters such as distance to the screen, distance to the first minimum, and the wavelength of the laser provided.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to apply a diffraction equation but encounters an incorrect result. Some participants suggest using an alternative diffraction equation and question the accuracy of the distance used in the calculations.

Discussion Status

The discussion is ongoing, with participants exploring different approaches to the problem. Some guidance has been offered regarding the use of diffraction equations, and there is recognition of potential discrepancies in the original poster's calculations.

Contextual Notes

There is a noted inconsistency in the distance measurement provided by the original poster, which may affect the calculations. The problem is framed within the context of homework, implying constraints on the methods that can be used.

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Optics--Diffraction of Thin Hair

Homework Statement



A human hair is illuminated with a laser and it produces a diffraction pattern on a screen 1.09 m away. If the distance from the center to the first minimum is 4.8 mm and the wavelength of the laser is 748 nm, what is the thickness of the hair? Express your answer in mm.


Homework Equations



wavelength = (x/m)*(w/l)

x= distance from central maximum to position of the minimum m
l= distance
w= width
m = minimum

The Attempt at a Solution



I converted 748nm to mm and 1.9m to mm and plugged in the values into the above equation and got .296 mm approximately. I set m = 1, because I thought it was asking for the 1st minimum. And x = 4.8...but the answer I got is wrong. Any help?
 
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I didn't go through your question, but I would have used the diffraction equation:

[tex]d\sin\theta=m\lambda[/tex]

You can treat an opaque body as a "slit". See Babinet's Principle
 


In the problem you say 1.09 m and then you use 1.9 m.
With 1.09 m you get around 170 microns (or 0.17 mm) which is OK for the thickness of hair.
 


Thank you very much!
 

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