Optics-Diffraction of Thin Hair

  • Thread starter Thread starter sheri1987
  • Start date Start date
  • Tags Tags
    Hair
Click For Summary
SUMMARY

The diffraction pattern produced by a human hair illuminated with a laser was analyzed to determine the hair's thickness. Using the wavelength of 748 nm and the distance to the first minimum of 4.8 mm, the correct thickness calculation yields approximately 0.17 mm when applying the diffraction equation d*sin(θ) = mλ. The initial attempt incorrectly used a distance of 1.9 m instead of the correct 1.09 m, leading to an erroneous result of 0.296 mm. The discussion emphasizes the importance of accurate measurements and the application of Babinet's Principle in diffraction problems.

PREREQUISITES
  • Understanding of diffraction principles in optics
  • Familiarity with Babinet's Principle
  • Knowledge of the diffraction equation d*sin(θ) = mλ
  • Ability to convert units (e.g., nm to mm)
NEXT STEPS
  • Study the application of Babinet's Principle in optical diffraction
  • Learn about the diffraction patterns produced by different slit widths
  • Explore the effects of wavelength on diffraction patterns
  • Investigate the relationship between distance to the screen and diffraction minima
USEFUL FOR

Students and educators in physics, particularly those focusing on optics and wave phenomena, as well as anyone interested in practical applications of diffraction in real-world scenarios.

sheri1987
Messages
47
Reaction score
0
Optics--Diffraction of Thin Hair

Homework Statement



A human hair is illuminated with a laser and it produces a diffraction pattern on a screen 1.09 m away. If the distance from the center to the first minimum is 4.8 mm and the wavelength of the laser is 748 nm, what is the thickness of the hair? Express your answer in mm.


Homework Equations



wavelength = (x/m)*(w/l)

x= distance from central maximum to position of the minimum m
l= distance
w= width
m = minimum

The Attempt at a Solution



I converted 748nm to mm and 1.9m to mm and plugged in the values into the above equation and got .296 mm approximately. I set m = 1, because I thought it was asking for the 1st minimum. And x = 4.8...but the answer I got is wrong. Any help?
 
Physics news on Phys.org


I didn't go through your question, but I would have used the diffraction equation:

d\sin\theta=m\lambda

You can treat an opaque body as a "slit". See Babinet's Principle
 


In the problem you say 1.09 m and then you use 1.9 m.
With 1.09 m you get around 170 microns (or 0.17 mm) which is OK for the thickness of hair.
 


Thank you very much!
 

Similar threads

  • · Replies 11 ·
Replies
11
Views
2K
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
Replies
8
Views
4K
  • · Replies 5 ·
Replies
5
Views
9K
  • · Replies 10 ·
Replies
10
Views
9K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 3 ·
Replies
3
Views
5K