Optimizing Multivariate Function with Lagrange Multiplier Method

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Homework Help Overview

The discussion revolves around finding the stationary value of a multivariate function defined as \( f(u,v,w) = \left( \frac{c}{u} \right)^m + \left( \frac{d}{v} \right)^m + \left( \frac{e}{w} \right)^m \) under the constraint \( u^2 + v^2 + w^2 = t^2 \). The variables \( u, v, w \) are constrained to be positive, along with constants \( c, d, e, t \) and a positive integer \( m \).

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the formulation of the auxiliary function and the resulting equations derived from the method of Lagrange multipliers. There is an exploration of rearranging these equations to express \( u^2, v^2, w^2 \) in terms of the constraint. Some participants suggest eliminating the Lagrange multiplier \( \lambda \) by dividing the equations, while others express confusion about how to proceed after obtaining expressions for \( u^{m+2}, v^{m+2}, w^{m+2} \).

Discussion Status

The discussion is ongoing, with participants sharing their understanding and approaches to the problem. Some guidance has been offered regarding the elimination of \( \lambda \) and rewriting the equations, but there is no explicit consensus on the next steps or a complete solution.

Contextual Notes

Participants note the challenge of rearranging the derived equations and the complexity introduced by the powers of \( m \). There is an acknowledgment of the need to work within the constraints of the problem while maintaining the positivity of the variables involved.

hawaiifiver
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Homework Statement



Find the stationary value of

$$ f(u,v,w) = \left( \frac{c}{u} \right)^m + \left( \frac{d}{v} \right)^m + \left( \frac{e}{w} \right)^m $$

Constraint: $$ u^2 + v^2 + w^2 = t^2 $$

Note: $$ u, v, w > 0 $$. $$ c,d, e, t > 0 $$. $$ m > 0 $$ and is a positive integer.

Homework Equations



I have found the auxiliary function:

$$ F = \left( \frac{c}{u} \right)^m + \left( \frac{d}{v} \right)^m + \left( \frac{e}{w} \right)^m - \lambda ( u^2 + v^2 + w^2 - t^2) $$

and

$$ F_u = \frac{- m c^m}{ u^{m+1}} - 2\lambda u = 0 $$

$$ F_v = \frac{- m d^m}{ v^{m+1}} - 2\lambda v = 0 $$

$$ F_w = \frac{- m e^m}{ w^{m+1}} - 2\lambda w = 0 $$

The Attempt at a Solution



Its after this I am having difficult. I don't understand what to do. I assume I have to rearrange the above equations to get $$ u^2, v^2, w^2 $$ and substitute into the constraint, but I can't see how to do that because I get expressions for $$ u^{m + 2} , v^{m+2} , w^{m+2} $$ . Help please.

The Attempt at a Solution


Homework Statement


Homework Equations


The Attempt at a Solution


Homework Statement


Homework Equations


The Attempt at a Solution


Homework Statement


Homework Equations


The Attempt at a Solution


Homework Statement


Homework Equations


The Attempt at a Solution


Homework Statement


Homework Equations


The Attempt at a Solution

 
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hawaiifiver said:

Homework Statement



Find the stationary value of

$$ f(u,v,w) = \left( \frac{c}{u} \right)^m + \left( \frac{d}{v} \right)^m + \left( \frac{e}{w} \right)^m $$

Constraint: $$ u^2 + v^2 + w^2 = t^2 $$

Note: $$ u, v, w > 0 $$. $$ c,d, e, t > 0 $$. $$ m > 0 $$ and is a positive integer.

Homework Equations



I have found the auxiliary function:

$$ F = \left( \frac{c}{u} \right)^m + \left( \frac{d}{v} \right)^m + \left( \frac{e}{w} \right)^m - \lambda ( u^2 + v^2 + w^2 - t^2) $$

and

$$ F_u = \frac{- m c^m}{ u^{m+1}} - 2\lambda u = 0 $$

$$ F_v = \frac{- m d^m}{ v^{m+1}} - 2\lambda v = 0 $$

$$ F_w = \frac{- m e^m}{ w^{m+1}} - 2\lambda w = 0 $$
Okay, that's good. What I would do is switch all of those "[itex]\lambda[/itex]" terms to the right:
[itex]\frac{-m c^m}{u^{m+1}}= 2\lambda u[/itex]
[itex]\frac{-m d^m}{v^{m+1}}= 2\lambda v[/itex]
[itex]\frac{-m d^m}{w^{m+1}}= 2\lambda w[/itex]

(In fact, to find extrema of f with constraint g= constant, I tend to think of the Lagrange multiplier condition as [itex]\nabla f= \lambda \nabla g[/itex] rather than using the "auxiliary function" [itex]f+ \lambda g[/itex]. It gives the same result, of course.)

Now, since a particular value of [itex]\lambda[/itex] is not part of the solution start by eliminating [itex]\lambda[/itex] by dividing one equation by another. Dividing the first equation by the second, for example, gives
[tex]\left(\frac{c}{d}\right)^m\left(\frac{v}{u}\right)^{m+1}= \frac{u}{v}[/tex]
which gives
[tex]\left(\frac{v}{u}\right)^{m+2}= \left(\frac{d}{c}\right)^m[/tex]
and similarly for the other equations.

The Attempt at a Solution



Its after this I am having difficult. I don't understand what to do. I assume I have to rearrange the above equations to get $$ u^2, v^2, w^2 $$ and substitute into the constraint, but I can't see how to do that because I get expressions for $$ u^{m + 2} , v^{m+2} , w^{m+2} $$ . Help please.
 
hawaiifiver said:

Homework Statement



Find the stationary value of

$$ f(u,v,w) = \left( \frac{c}{u} \right)^m + \left( \frac{d}{v} \right)^m + \left( \frac{e}{w} \right)^m $$

Constraint: $$ u^2 + v^2 + w^2 = t^2 $$

Note: $$ u, v, w > 0 $$. $$ c,d, e, t > 0 $$. $$ m > 0 $$ and is a positive integer.


Homework Equations



I have found the auxiliary function:

$$ F = \left( \frac{c}{u} \right)^m + \left( \frac{d}{v} \right)^m + \left( \frac{e}{w} \right)^m - \lambda ( u^2 + v^2 + w^2 - t^2) $$

and

$$ F_u = \frac{- m c^m}{ u^{m+1}} - 2\lambda u = 0 $$

$$ F_v = \frac{- m d^m}{ v^{m+1}} - 2\lambda v = 0 $$

$$ F_w = \frac{- m e^m}{ w^{m+1}} - 2\lambda w = 0 $$



The Attempt at a Solution



Its after this I am having difficult. I don't understand what to do. I assume I have to rearrange the above equations to get $$ u^2, v^2, w^2 $$ and substitute into the constraint, but I can't see how to do that because I get expressions for $$ u^{m + 2} , v^{m+2} , w^{m+2} $$ . Help please.







The Attempt at a Solution


You have expressions for [itex]u^{m + 2} , v^{m+2} , w^{m+2}[/itex] in terms of λ. You can take (m+2) roots, to get [itex]u, v, w[/itex]. You can then substitute these expressions into the constraint, to get a single, simple equation for λ. Actually, it is easier to re-write everything in terms of μ = -λ; that will eliminate a lot of minus signs in the equations and solutions.

RGV
 
Thank you both. I'm understanding this problem now.
 

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