# Oreder of groups and their elements

1. Nov 8, 2008

### Bellarosa

Show that any group of even order has at least an element of order 2
2. Relevant equations

3. I know that the order of a groups tells you how many elements the group consist, but just randomly assuming that it has at least an order of 2 is what I can't really understand. For example |G| = 6, which means that G = {a,b,c,d,e,f} I know that one of its element is the identity element which is e, but the order of the other elements can all be 2, or one element can only have order 2. I just need to understand how the order of a group relates to he order of its element.

2. Nov 8, 2008

### Dick

If there is no element of order 2 then g is not equal to g^(-1) for every element in G except for e (the identity), right? Do you see it yet?

3. Nov 8, 2008

### Bellarosa

which means that the group will only have one element right...I'm understanding but it's still a bit confusing...

4. Nov 8, 2008

### Dick

The group will be split into pairs {g,g^(-1)} which all have two elements and finally {e} which only has one element. Looks to me like that would imply the order of the group would be odd. Seem so to you?

5. Nov 8, 2008

### Bellarosa

yes the group will have an odd order

6. Nov 8, 2008

### Dick

Right. So any group that has no element of order two has odd order. So if a group has even order....?

7. Nov 8, 2008

### Bellarosa

then how can you determine which elements are of order 2

8. Nov 8, 2008

### Dick

No, if you know a group has order eight, then one element is it's own inverse (so has order two).

9. Nov 8, 2008

### Dick

You can't until you know what the group is. You just know there must be one.

10. Nov 8, 2008

### Bellarosa

ok I think I get it ... you're saying that for example G = {e, a, b, c} then if a has an order of two then a^2 = e, or can you give me a general example?

11. Nov 9, 2008

### Dick

Take Z_6. The set of integers mod 6 under addition. The order of the group is 6 which is even. So one of those integers must have order two. Which one?

12. Nov 9, 2008

### Bellarosa

3...this I understand I just have trouble showing how an unspecified group of even order has an element of order 2

13. Nov 9, 2008

### Dick

That - is - what - you - are - supposed - to - prove. You don't have to say which one it is, you are just supposed to show it exists.

14. Nov 10, 2008

### Bellarosa

ok got you

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