Orienational order parameter in isotropic systems

In summary, the conversation is about the use of an order parameter, S, in NMR and liquid crystal studies. S represents the angle of a molecule with a reference vector and corresponds to a second-order Legendre polynomial. It is often observed that in an isotropic environment, S=0, and in a well-aligned environment, S=1. The reason for S=0 in an isotropic environment is due to the average of cos^2 being 1/3 over a solid angle of 4π.
  • #1
Liam79
1
0
Hi everyone,

I have what may be a dummy question. In NMR or in the study of liquid crystals for example, an order parameter [itex]S[/itex] is often used:
[itex]S=\left\langle\frac{1}{2}\left(3\cos^{2}\theta-1\right)\right\rangle[/itex]
with [itex]\theta[/itex] the angle of the molecule with a "director" (the magnetic field in NMR, the normal to a membrane for lipids, the global direction in a nematic phase etc). [itex]S[/itex] corresponds to a second-order Legendre polynomial.
I have often read that in an isotropic environment, [itex]S=0[/itex] whereas when all the molecules are well aligned with the reference vector (director), [itex]S=1[/itex]. I understand why [itex]S=1[/itex] as [itex]\theta=0°[/itex] but I can't find why [itex]S=0[/itex] when all the orientations are random.
Can anyone help me?

Liam
 
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  • #2
For isotropic distribution the average of cos^2 is 1/3.
The average (these brackets) imply an integral over solid angle of 4π.
 
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