Oscilloscope Error: Measuring Sinusoidal Wave

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The discussion revolves around measuring the error of an oscilloscope when used to analyze a sinusoidal wave, specifically when the actual wave resembles a sawtooth shape. Participants question how to define the true value of the sinusoidal wave, suggesting a peak of 4V based on the provided range. Clarification is sought regarding the phrase "being prepared" for measuring a sinusoid, with inquiries about its previous usage in exercises or labs. There is also uncertainty about whether the oscilloscope is indeed the instrument referenced in the problem statement. The conversation highlights the need for precise definitions and understanding of measurement contexts in waveform analysis.
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Homework Statement


"An instrument (oscilloscope) is prepared to measure a sinusoidal periodic wave, compute the measurement error if the same instrument is used to measure the wave indicated in figure 1
Untitled.png


(The wave is much more like a sawtooth wave, sorry for bad drawing)

Homework Equations


((Measured-True)/(Measured)) × 100

The Attempt at a Solution



Actually, I don't how to start, should I assume that sinusoidal wave is 4V peak (from 6V to 10V above, and 6V to 2V below) and substracting the values?

Untitled2.png
 
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The key to this probably lies in the meaning of an instrument "being prepared" for measuring a sinusoid. Have you encountered this phrase in any earlier exercises, or in the laboratory?

Are you sure the question says it's an oscilloscope that is the instrument that is being prepared, or is that your interpretation?
 

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