Oscilloscope Error: Measuring Sinusoidal Wave

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SUMMARY

The discussion focuses on measuring the error of a sinusoidal wave using an oscilloscope, specifically addressing the formula for calculating measurement error: ((Measured-True)/(Measured)) × 100. The participant contemplates whether to assume a peak value of 4V for the sinusoidal wave, derived from a range of 6V to 10V and 6V to 2V. The conversation highlights the importance of understanding the phrase "being prepared" in the context of oscilloscope measurements, suggesting that clarity on this terminology is crucial for accurate error computation.

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Homework Statement


"An instrument (oscilloscope) is prepared to measure a sinusoidal periodic wave, compute the measurement error if the same instrument is used to measure the wave indicated in figure 1
Untitled.png


(The wave is much more like a sawtooth wave, sorry for bad drawing)

Homework Equations


((Measured-True)/(Measured)) × 100

The Attempt at a Solution



Actually, I don't how to start, should I assume that sinusoidal wave is 4V peak (from 6V to 10V above, and 6V to 2V below) and substracting the values?

Untitled2.png
 
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The key to this probably lies in the meaning of an instrument "being prepared" for measuring a sinusoid. Have you encountered this phrase in any earlier exercises, or in the laboratory?

Are you sure the question says it's an oscilloscope that is the instrument that is being prepared, or is that your interpretation?
 

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