Other definition for fourier series

Jhenrique
Messages
676
Reaction score
4
Is correct to define Fourier series like:

f(t)=\sum_{k=0}^{\infty}a_k \cos \left (\frac{2 \pi k t}{T} \right ) + b_k \sin \left (\frac{2 \pi k t}{T} \right )

Where ak and bk:

a_k=\frac{1}{T} \int_{-T}^{+T} f(t) \cos \left (\frac{2 \pi k t}{T} \right ) dt

b_k=\frac{1}{T} \int_{-T}^{+T} f(t) \sin \left (\frac{2 \pi k t}{T} \right ) dt

?
 
Physics news on Phys.org
No. You are counting the period twice.
If this were true, could you expand something like \cos \left (\frac{\pi t}{T} \right )?
 
I don't understand your answer
 
I take this topic to introduce another question: in wikipedia, I found others difinitions to Fourier series:

f(t)=A_0+\sum_{n=1}^{\infty } A_n cos\left ( \frac{2 \pi n t}{T}-\phi_n \right )
where:

##A_0 = \frac{1}{2}a_0##
##A_n = \sqrt{a_{n}^{2}+b_{n}^{2}}##
##\phi_n = tan^{-1}\left ( \frac{b_n}{a_n} \right )##


and:

f(t)=\gamma_0+2\sum_{n=1}^{\infty } \gamma_n cos\left ( \frac{2 \pi n t}{T}+\varphi_n \right )
where:

##\gamma_0 = c_0##
##\gamma_n = abs(c_n)##
##\varphi_n = arg(c_n)##



I'd like to know if ##\varphi_n## is or isn't equal to ##\phi_n## ?
 
Thread 'Direction Fields and Isoclines'
I sketched the isoclines for $$ m=-1,0,1,2 $$. Since both $$ \frac{dy}{dx} $$ and $$ D_{y} \frac{dy}{dx} $$ are continuous on the square region R defined by $$ -4\leq x \leq 4, -4 \leq y \leq 4 $$ the existence and uniqueness theorem guarantees that if we pick a point in the interior that lies on an isocline there will be a unique differentiable function (solution) passing through that point. I understand that a solution exists but I unsure how to actually sketch it. For example, consider a...

Similar threads

Back
Top