# Output of the circuit as function of time

1. Aug 9, 2009

### atan691988

can anyone help me with this>>>

* If the input is Given by Vin = V0 cosωt, plot the output of the circuit as function of time. assume an ideal diode model. *

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2. Aug 9, 2009

3. Aug 9, 2009

### Redbelly98

Staff Emeritus
Often, in introductory courses, "ideal diode" means zero forward voltage and zero reverse current.

4. Aug 9, 2009

### rootX

Write V_out in terms of the DC voltage source 2V and v_in.

When V-in* is more negative than -2, diode is on so replace it with short circuit. Else diode is off, replace it with open circuit.

But, does it really matter whether diode is on/off in this circuit?

Last edited: Aug 9, 2009
5. Aug 9, 2009

### Redbelly98

Staff Emeritus
Now that I can see the circuit ... no, you're right it does not affect Vout here.

6. Aug 9, 2009

### fleem

Gahh! I didn't look at the graphic because I thought it was one of those "pending admin approval" things. Its a link! This is easy.

Hint 1: An ideal voltage source is unaffected by the current that is being drawn from it.
Hint 2: Consider V_in and the battery as your "ideal voltage source"

(Sheesh I practically gave you the answer)

7. Aug 9, 2009

### Redbelly98

Staff Emeritus
It was a "pending admin approval" thing. Eventually an admin approved it.

8. Aug 9, 2009

### rootX

That was question to the OP because I didn't want to provide him a direct answer :rofl:

9. Aug 9, 2009

### Redbelly98

Staff Emeritus
Oops.

10. Aug 11, 2009

### atan691988

hahaha. thanks for all your replies guys.