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Output of the circuit as function of time

  1. Aug 9, 2009 #1
    can anyone help me with this>>>

    * If the input is Given by Vin = V0 cosωt, plot the output of the circuit as function of time. assume an ideal diode model. *
     

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  3. Aug 9, 2009 #2
  4. Aug 9, 2009 #3

    Redbelly98

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    Often, in introductory courses, "ideal diode" means zero forward voltage and zero reverse current.
     
  5. Aug 9, 2009 #4
    Write V_out in terms of the DC voltage source 2V and v_in.

    When V-in* is more negative than -2, diode is on so replace it with short circuit. Else diode is off, replace it with open circuit.

    But, does it really matter whether diode is on/off in this circuit?
     
    Last edited: Aug 9, 2009
  6. Aug 9, 2009 #5

    Redbelly98

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    Now that I can see the circuit ... no, you're right it does not affect Vout here.
     
  7. Aug 9, 2009 #6
    Gahh! I didn't look at the graphic because I thought it was one of those "pending admin approval" things. Its a link! This is easy.

    Hint 1: An ideal voltage source is unaffected by the current that is being drawn from it.
    Hint 2: Consider V_in and the battery as your "ideal voltage source"

    (Sheesh I practically gave you the answer)
     
  8. Aug 9, 2009 #7

    Redbelly98

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    It was a "pending admin approval" thing. Eventually an admin approved it.
     
  9. Aug 9, 2009 #8
    That was question to the OP because I didn't want to provide him a direct answer :rofl:
     
  10. Aug 9, 2009 #9

    Redbelly98

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  11. Aug 11, 2009 #10
    hahaha. thanks for all your replies guys.

    I've already figure it out..

    but really thanks to all :D

    <<< mods can close these thread.
     
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