Output of the circuit as function of time

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Discussion Overview

The discussion revolves around analyzing the output of a circuit as a function of time, given an input voltage described by Vin = V0 cosωt, while assuming an ideal diode model. The focus includes theoretical aspects of circuit behavior and the implications of diode operation on output voltage.

Discussion Character

  • Exploratory
  • Technical explanation
  • Conceptual clarification
  • Homework-related

Main Points Raised

  • Some participants discuss the characteristics of the ideal diode model, noting it typically implies zero forward voltage and zero reverse current.
  • One participant suggests writing V_out in terms of a DC voltage source and the input voltage, indicating conditions under which the diode is on or off.
  • There is a question raised about the relevance of the diode's state (on/off) in the circuit, with a later reply affirming that it does not affect V_out in this case.
  • Hints are provided regarding the nature of an ideal voltage source and its independence from the current drawn, suggesting a consideration of the input voltage and the battery as an ideal voltage source.
  • Participants express some confusion regarding the visibility of the circuit schematic, with one noting that it was initially pending admin approval.

Areas of Agreement / Disagreement

Participants generally agree that the state of the diode does not affect the output voltage in this specific circuit configuration, although there are varying interpretations of the ideal diode model and its implications.

Contextual Notes

Some assumptions about the circuit's configuration and the behavior of the ideal diode may not be fully articulated, and the discussion does not resolve all potential interpretations of the diode's role.

Who May Find This Useful

This discussion may be useful for students or individuals interested in circuit analysis, particularly those studying diode behavior in electrical engineering contexts.

atan691988
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can anyone help me with this>>>

* If the input is Given by Vin = V0 cosωt, plot the output of the circuit as function of time. assume an ideal diode model. *
 

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Often, in introductory courses, "ideal diode" means zero forward voltage and zero reverse current.
 
Write V_out in terms of the DC voltage source 2V and v_in.

When V-in* is more negative than -2, diode is on so replace it with short circuit. Else diode is off, replace it with open circuit.

But, does it really matter whether diode is on/off in this circuit?
 
Last edited:
rootX said:
But, does it really matter whether diode is on/off in this circuit?

Now that I can see the circuit ... no, you're right it does not affect Vout here.
 
Gahh! I didn't look at the graphic because I thought it was one of those "pending admin approval" things. Its a link! This is easy.

Hint 1: An ideal voltage source is unaffected by the current that is being drawn from it.
Hint 2: Consider V_in and the battery as your "ideal voltage source"

(Sheesh I practically gave you the answer)
 
fleem said:
Gahh! I didn't look at the graphic because I thought it was one of those "pending admin approval" things. Its a link! This is easy.

It was a "pending admin approval" thing. Eventually an admin approved it.
 
Redbelly98 said:
Now that I can see the circuit ... no, you're right it does not affect Vout here.

That was question to the OP because I didn't want to provide him a direct answer :smile:
 
  • #10
hahaha. thanks for all your replies guys.

I've already figure it out..

but really thanks to all :D

<<< mods can close these thread.
 

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