Over or Under? Analyzing the 50th Partial Sum of an Alternating Series

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SUMMARY

The 50th partial sum, s_50, of the alternating series defined by the summation [(-1)^(n-1)] / n from 1 to infinity is an underestimate of the total sum. This conclusion is supported by the fact that the sequence b_n = 1/n is divergent and increasing, which aligns with the properties of alternating series. The discussion highlights the relationship between the behavior of partial sums and the convergence of the series, ultimately confirming that the book's assertion of s_50 being an underestimate is accurate.

PREREQUISITES
  • Understanding of alternating series and their convergence properties
  • Familiarity with the concept of partial sums in series
  • Knowledge of the divergence of the harmonic series
  • Basic calculus, particularly limits and series analysis
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  • Study the properties of alternating series and the Alternating Series Test
  • Learn about the convergence criteria for series, including the comparison test
  • Explore the relationship between partial sums and convergence in more complex series
  • Investigate the derivation and applications of the natural logarithm, specifically ln(2)
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Students studying calculus, particularly those focusing on series and convergence, as well as educators looking for clear explanations of alternating series behavior.

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Homework Statement


Is the 50th partial sum, s_50, of the alternating series, "summation [(-1)^(n-1)] / n from 1-->infinity" an overestimate or an underestimate of the total sum? Explain



The Attempt at a Solution


First concern: Isn't every partial sum an underestimate for an increasing sequence and an overestimate for a decreasing sequence?

Secondly, I saw that b_n = 1/n, which is a divergent sum. So since it is increasing and divergent, wouldn't the partial sum s_50 be an underestimate?

This seems to be too easy a conclusion, so does anyone know if there is any other way to justify it?
 
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The book says it is an underestimate.
 
I think that its an overestimate, notice that its 1 - (1/2) + (1/3) - (1/4) + (1/5) - ... = 1 - (1/2 - 1/3) - (1/4 - 1/5) - ..., in reality you're always subtracting from 1. By the way, this sum is equal to ln(2).

Sorry for my previous post, I've messed up a bit :)
 

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